3(u+4)=-2(5u-2)+7u

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Solution for 3(u+4)=-2(5u-2)+7u equation: 



3(u+4)=-2(5u-2)+7u

We move all terms to the left:

3(u+4)-(-2(5u-2)+7u)=0

We multiply parentheses

3u-(-2(5u-2)+7u)+12=0



We calculate terms in parentheses: -(-2(5u-2)+7u), so:

-2(5u-2)+7u

We add all the numbers together, and all the variables

7u-2(5u-2)

We multiply parentheses

7u-10u+4

We add all the numbers together, and all the variables

-3u+4

Back to the equation:

-(-3u+4)



We get rid of parentheses

3u+3u-4+12=0

We add all the numbers together, and all the variables

6u+8=0

We move all terms containing u to the left, all other terms to the right

6u=-8

u=-8/6

u=-1+1/3

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