3(u+4)=-7(2u-2)+u

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Solution for 3(u+4)=-7(2u-2)+u equation: 



3(u+4)=-7(2u-2)+u

We move all terms to the left:

3(u+4)-(-7(2u-2)+u)=0

We multiply parentheses

3u-(-7(2u-2)+u)+12=0



We calculate terms in parentheses: -(-7(2u-2)+u), so:

-7(2u-2)+u

We add all the numbers together, and all the variables

u-7(2u-2)

We multiply parentheses

u-14u+14

We add all the numbers together, and all the variables

-13u+14

Back to the equation:

-(-13u+14)



We get rid of parentheses

3u+13u-14+12=0

We add all the numbers together, and all the variables

16u-2=0

We move all terms containing u to the left, all other terms to the right

16u=2

u=2/16

u=1/8

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