3(u+4)=3(6u-1)+6

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Solution for 3(u+4)=3(6u-1)+6 equation: 



3(u+4)=3(6u-1)+6

We move all terms to the left:

3(u+4)-(3(6u-1)+6)=0

We multiply parentheses

3u-(3(6u-1)+6)+12=0



We calculate terms in parentheses: -(3(6u-1)+6), so:

3(6u-1)+6

We multiply parentheses

18u-3+6

We add all the numbers together, and all the variables

18u+3

Back to the equation:

-(18u+3)



We get rid of parentheses

3u-18u-3+12=0

We add all the numbers together, and all the variables

-15u+9=0

We move all terms containing u to the left, all other terms to the right

-15u=-9

u=-9/-15

u=3/5

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