3(u+4)=3(6u-1)+6u

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Solution for 3(u+4)=3(6u-1)+6u equation: 



3(u+4)=3(6u-1)+6u

We move all terms to the left:

3(u+4)-(3(6u-1)+6u)=0

We multiply parentheses

3u-(3(6u-1)+6u)+12=0



We calculate terms in parentheses: -(3(6u-1)+6u), so:

3(6u-1)+6u

We add all the numbers together, and all the variables

6u+3(6u-1)

We multiply parentheses

6u+18u-3

We add all the numbers together, and all the variables

24u-3

Back to the equation:

-(24u-3)



We get rid of parentheses

3u-24u+3+12=0

We add all the numbers together, and all the variables

-21u+15=0

We move all terms containing u to the left, all other terms to the right

-21u=-15

u=-15/-21

u=5/7

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