3(u+5)=-3u+27

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Solution for 3(u+5)=-3u+27 equation: 



3(u+5)=-3u+27

We move all terms to the left:

3(u+5)-(-3u+27)=0

We multiply parentheses

3u-(-3u+27)+15=0

We get rid of parentheses

3u+3u-27+15=0

We add all the numbers together, and all the variables

6u-12=0

We move all terms containing u to the left, all other terms to the right

6u=12

u=12/6

u=2

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