3(u+5)=2u-4+uC

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Solution for 3(u+5)=2u-4+uC equation: 



3(u+5)=2u-4+u

We move all terms to the left:

3(u+5)-(2u-4+u)=0

We add all the numbers together, and all the variables

3(u+5)-(3u-4)=0

We multiply parentheses

3u-(3u-4)+15=0

We get rid of parentheses

3u-3u+4+15=0

We add all the numbers together, and all the variables

19!=0

There is no solution for this equation

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