3(u+6)=-3(3u-5)+3u

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Solution for 3(u+6)=-3(3u-5)+3u equation: 



3(u+6)=-3(3u-5)+3u

We move all terms to the left:

3(u+6)-(-3(3u-5)+3u)=0

We multiply parentheses

3u-(-3(3u-5)+3u)+18=0



We calculate terms in parentheses: -(-3(3u-5)+3u), so:

-3(3u-5)+3u

We add all the numbers together, and all the variables

3u-3(3u-5)

We multiply parentheses

3u-9u+15

We add all the numbers together, and all the variables

-6u+15

Back to the equation:

-(-6u+15)



We get rid of parentheses

3u+6u-15+18=0

We add all the numbers together, and all the variables

9u+3=0

We move all terms containing u to the left, all other terms to the right

9u=-3

u=-3/9

u=-1/3

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