3(u+9)=-3(6u-5)+6u

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Solution for 3(u+9)=-3(6u-5)+6u equation: 



3(u+9)=-3(6u-5)+6u

We move all terms to the left:

3(u+9)-(-3(6u-5)+6u)=0

We multiply parentheses

3u-(-3(6u-5)+6u)+27=0



We calculate terms in parentheses: -(-3(6u-5)+6u), so:

-3(6u-5)+6u

We add all the numbers together, and all the variables

6u-3(6u-5)

We multiply parentheses

6u-18u+15

We add all the numbers together, and all the variables

-12u+15

Back to the equation:

-(-12u+15)



We get rid of parentheses

3u+12u-15+27=0

We add all the numbers together, and all the variables

15u+12=0

We move all terms containing u to the left, all other terms to the right

15u=-12

u=-12/15

u=-4/5

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