3(u+9)=-3(6u-5)+6u

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Solution for 3(u+9)=-3(6u-5)+6u equation:



3(u+9)=-3(6u-5)+6u
We move all terms to the left:
3(u+9)-(-3(6u-5)+6u)=0
We multiply parentheses
3u-(-3(6u-5)+6u)+27=0
We calculate terms in parentheses: -(-3(6u-5)+6u), so:
-3(6u-5)+6u
We add all the numbers together, and all the variables
6u-3(6u-5)
We multiply parentheses
6u-18u+15
We add all the numbers together, and all the variables
-12u+15
Back to the equation:
-(-12u+15)
We get rid of parentheses
3u+12u-15+27=0
We add all the numbers together, and all the variables
15u+12=0
We move all terms containing u to the left, all other terms to the right
15u=-12
u=-12/15
u=-4/5

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