3(u+9)=-5(4u-3)+7u

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Solution for 3(u+9)=-5(4u-3)+7u equation: 



3(u+9)=-5(4u-3)+7u

We move all terms to the left:

3(u+9)-(-5(4u-3)+7u)=0

We multiply parentheses

3u-(-5(4u-3)+7u)+27=0



We calculate terms in parentheses: -(-5(4u-3)+7u), so:

-5(4u-3)+7u

We add all the numbers together, and all the variables

7u-5(4u-3)

We multiply parentheses

7u-20u+15

We add all the numbers together, and all the variables

-13u+15

Back to the equation:

-(-13u+15)



We get rid of parentheses

3u+13u-15+27=0

We add all the numbers together, and all the variables

16u+12=0

We move all terms containing u to the left, all other terms to the right

16u=-12

u=-12/16

u=-3/4

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