3(u-1)-1=3(-6u+2)-u

Solution for 3(u-1)-1=3(-6u+2)-u equation:

3(u-1)-1=3(-6u+2)-u

We move all terms to the left:

3(u-1)-1-(3(-6u+2)-u)=0

We multiply parentheses

3u-(3(-6u+2)-u)-3-1=0


We calculate terms in parentheses: -(3(-6u+2)-u), so:

3(-6u+2)-u

We add all the numbers together, and all the variables

-1u+3(-6u+2)

We multiply parentheses

-1u-18u+6

We add all the numbers together, and all the variables

-19u+6

Back to the equation:

-(-19u+6)


We add all the numbers together, and all the variables

3u-(-19u+6)-4=0

We get rid of parentheses

3u+19u-6-4=0

We add all the numbers together, and all the variables

22u-10=0

We move all terms containing u to the left, all other terms to the right

22u=10

u=10/22

u=5/11