3(u-1)=3u+1-4(-4u-1)

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Solution for 3(u-1)=3u+1-4(-4u-1) equation: 



3(u-1)=3u+1-4(-4u-1)

We move all terms to the left:

3(u-1)-(3u+1-4(-4u-1))=0

We multiply parentheses

3u-(3u+1-4(-4u-1))-3=0



We calculate terms in parentheses: -(3u+1-4(-4u-1)), so:

3u+1-4(-4u-1)

determiningTheFunctionDomain
3u-4(-4u-1)+1

We multiply parentheses

3u+16u+4+1

We add all the numbers together, and all the variables

19u+5

Back to the equation:

-(19u+5)



We get rid of parentheses

3u-19u-5-3=0

We add all the numbers together, and all the variables

-16u-8=0

We move all terms containing u to the left, all other terms to the right

-16u=8

u=8/-16

u=-1/2

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