3(u-1)=5u+3-2(-6u-3)

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Solution for 3(u-1)=5u+3-2(-6u-3) equation: 



3(u-1)=5u+3-2(-6u-3)

We move all terms to the left:

3(u-1)-(5u+3-2(-6u-3))=0

We multiply parentheses

3u-(5u+3-2(-6u-3))-3=0



We calculate terms in parentheses: -(5u+3-2(-6u-3)), so:

5u+3-2(-6u-3)

determiningTheFunctionDomain
5u-2(-6u-3)+3

We multiply parentheses

5u+12u+6+3

We add all the numbers together, and all the variables

17u+9

Back to the equation:

-(17u+9)



We get rid of parentheses

3u-17u-9-3=0

We add all the numbers together, and all the variables

-14u-12=0

We move all terms containing u to the left, all other terms to the right

-14u=12

u=12/-14

u=-6/7

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