3(u-1)=5u+9-3(-4u-2)

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Solution for 3(u-1)=5u+9-3(-4u-2) equation: 



3(u-1)=5u+9-3(-4u-2)

We move all terms to the left:

3(u-1)-(5u+9-3(-4u-2))=0

We multiply parentheses

3u-(5u+9-3(-4u-2))-3=0



We calculate terms in parentheses: -(5u+9-3(-4u-2)), so:

5u+9-3(-4u-2)

determiningTheFunctionDomain
5u-3(-4u-2)+9

We multiply parentheses

5u+12u+6+9

We add all the numbers together, and all the variables

17u+15

Back to the equation:

-(17u+15)



We get rid of parentheses

3u-17u-15-3=0

We add all the numbers together, and all the variables

-14u-18=0

We move all terms containing u to the left, all other terms to the right

-14u=18

u=18/-14

u=-1+2/7

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