3(u-1)=6u+6-3(-3u-2)

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Solution for 3(u-1)=6u+6-3(-3u-2) equation: 



3(u-1)=6u+6-3(-3u-2)

We move all terms to the left:

3(u-1)-(6u+6-3(-3u-2))=0

We multiply parentheses

3u-(6u+6-3(-3u-2))-3=0



We calculate terms in parentheses: -(6u+6-3(-3u-2)), so:

6u+6-3(-3u-2)

determiningTheFunctionDomain
6u-3(-3u-2)+6

We multiply parentheses

6u+9u+6+6

We add all the numbers together, and all the variables

15u+12

Back to the equation:

-(15u+12)



We get rid of parentheses

3u-15u-12-3=0

We add all the numbers together, and all the variables

-12u-15=0

We move all terms containing u to the left, all other terms to the right

-12u=15

u=15/-12

u=-1+1/4

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