3(u-1)=7u+3-2(-2u-2)

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Solution for 3(u-1)=7u+3-2(-2u-2) equation: 



3(u-1)=7u+3-2(-2u-2)

We move all terms to the left:

3(u-1)-(7u+3-2(-2u-2))=0

We multiply parentheses

3u-(7u+3-2(-2u-2))-3=0



We calculate terms in parentheses: -(7u+3-2(-2u-2)), so:

7u+3-2(-2u-2)

determiningTheFunctionDomain
7u-2(-2u-2)+3

We multiply parentheses

7u+4u+4+3

We add all the numbers together, and all the variables

11u+7

Back to the equation:

-(11u+7)



We get rid of parentheses

3u-11u-7-3=0

We add all the numbers together, and all the variables

-8u-10=0

We move all terms containing u to the left, all other terms to the right

-8u=10

u=10/-8

u=-1+1/4

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