3(u-1)=9u+1-2(-2u-5)

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Solution for 3(u-1)=9u+1-2(-2u-5) equation: 



3(u-1)=9u+1-2(-2u-5)

We move all terms to the left:

3(u-1)-(9u+1-2(-2u-5))=0

We multiply parentheses

3u-(9u+1-2(-2u-5))-3=0



We calculate terms in parentheses: -(9u+1-2(-2u-5)), so:

9u+1-2(-2u-5)

determiningTheFunctionDomain
9u-2(-2u-5)+1

We multiply parentheses

9u+4u+10+1

We add all the numbers together, and all the variables

13u+11

Back to the equation:

-(13u+11)



We get rid of parentheses

3u-13u-11-3=0

We add all the numbers together, and all the variables

-10u-14=0

We move all terms containing u to the left, all other terms to the right

-10u=14

u=14/-10

u=-1+2/5

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