3(u-1)=u+3-2(-9u-3)

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Solution for 3(u-1)=u+3-2(-9u-3) equation: 



3(u-1)=u+3-2(-9u-3)

We move all terms to the left:

3(u-1)-(u+3-2(-9u-3))=0

We multiply parentheses

3u-(u+3-2(-9u-3))-3=0



We calculate terms in parentheses: -(u+3-2(-9u-3)), so:

u+3-2(-9u-3)

determiningTheFunctionDomain
u-2(-9u-3)+3

We multiply parentheses

u+18u+6+3

We add all the numbers together, and all the variables

19u+9

Back to the equation:

-(19u+9)



We get rid of parentheses

3u-19u-9-3=0

We add all the numbers together, and all the variables

-16u-12=0

We move all terms containing u to the left, all other terms to the right

-16u=12

u=12/-16

u=-3/4

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