3(u-1)=u+5-2(-5u-2)

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Solution for 3(u-1)=u+5-2(-5u-2) equation: 



3(u-1)=u+5-2(-5u-2)

We move all terms to the left:

3(u-1)-(u+5-2(-5u-2))=0

We multiply parentheses

3u-(u+5-2(-5u-2))-3=0



We calculate terms in parentheses: -(u+5-2(-5u-2)), so:

u+5-2(-5u-2)

determiningTheFunctionDomain
u-2(-5u-2)+5

We multiply parentheses

u+10u+4+5

We add all the numbers together, and all the variables

11u+9

Back to the equation:

-(11u+9)



We get rid of parentheses

3u-11u-9-3=0

We add all the numbers together, and all the variables

-8u-12=0

We move all terms containing u to the left, all other terms to the right

-8u=12

u=12/-8

u=-1+1/2

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