3(u-2)-3=-3(-5u+1)-3u

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Solution for 3(u-2)-3=-3(-5u+1)-3u equation: 



3(u-2)-3=-3(-5u+1)-3u

We move all terms to the left:

3(u-2)-3-(-3(-5u+1)-3u)=0

We multiply parentheses

3u-(-3(-5u+1)-3u)-6-3=0



We calculate terms in parentheses: -(-3(-5u+1)-3u), so:

-3(-5u+1)-3u

We add all the numbers together, and all the variables

-3u-3(-5u+1)

We multiply parentheses

-3u+15u-3

We add all the numbers together, and all the variables

12u-3

Back to the equation:

-(12u-3)



We add all the numbers together, and all the variables

3u-(12u-3)-9=0

We get rid of parentheses

3u-12u+3-9=0

We add all the numbers together, and all the variables

-9u-6=0

We move all terms containing u to the left, all other terms to the right

-9u=6

u=6/-9

u=-2/3

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