3(u-2)=7u+2-2(-5u-4)

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Solution for 3(u-2)=7u+2-2(-5u-4) equation: 



3(u-2)=7u+2-2(-5u-4)

We move all terms to the left:

3(u-2)-(7u+2-2(-5u-4))=0

We multiply parentheses

3u-(7u+2-2(-5u-4))-6=0



We calculate terms in parentheses: -(7u+2-2(-5u-4)), so:

7u+2-2(-5u-4)

determiningTheFunctionDomain
7u-2(-5u-4)+2

We multiply parentheses

7u+10u+8+2

We add all the numbers together, and all the variables

17u+10

Back to the equation:

-(17u+10)



We get rid of parentheses

3u-17u-10-6=0

We add all the numbers together, and all the variables

-14u-16=0

We move all terms containing u to the left, all other terms to the right

-14u=16

u=16/-14

u=-1+1/7

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