3(u-2)=7u+4-2(-2u-2)

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Solution for 3(u-2)=7u+4-2(-2u-2) equation: 



3(u-2)=7u+4-2(-2u-2)

We move all terms to the left:

3(u-2)-(7u+4-2(-2u-2))=0

We multiply parentheses

3u-(7u+4-2(-2u-2))-6=0



We calculate terms in parentheses: -(7u+4-2(-2u-2)), so:

7u+4-2(-2u-2)

determiningTheFunctionDomain
7u-2(-2u-2)+4

We multiply parentheses

7u+4u+4+4

We add all the numbers together, and all the variables

11u+8

Back to the equation:

-(11u+8)



We get rid of parentheses

3u-11u-8-6=0

We add all the numbers together, and all the variables

-8u-14=0

We move all terms containing u to the left, all other terms to the right

-8u=14

u=14/-8

u=-1+3/4

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