3(u-3)+6u=27

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Solution for 3(u-3)+6u=27 equation: 



3(u-3)+6u=27

We move all terms to the left:

3(u-3)+6u-(27)=0

We add all the numbers together, and all the variables

6u+3(u-3)-27=0

We multiply parentheses

6u+3u-9-27=0

We add all the numbers together, and all the variables

9u-36=0

We move all terms containing u to the left, all other terms to the right

9u=36

u=36/9

u=4

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