3(u-3)-1=-2(-2u+3)-7u

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Solution for 3(u-3)-1=-2(-2u+3)-7u equation: 



3(u-3)-1=-2(-2u+3)-7u

We move all terms to the left:

3(u-3)-1-(-2(-2u+3)-7u)=0

We multiply parentheses

3u-(-2(-2u+3)-7u)-9-1=0



We calculate terms in parentheses: -(-2(-2u+3)-7u), so:

-2(-2u+3)-7u

We add all the numbers together, and all the variables

-7u-2(-2u+3)

We multiply parentheses

-7u+4u-6

We add all the numbers together, and all the variables

-3u-6

Back to the equation:

-(-3u-6)



We add all the numbers together, and all the variables

3u-(-3u-6)-10=0

We get rid of parentheses

3u+3u+6-10=0

We add all the numbers together, and all the variables

6u-4=0

We move all terms containing u to the left, all other terms to the right

6u=4

u=4/6

u=2/3

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