3(u-3)-6=-5(-3u+5)-6u

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Solution for 3(u-3)-6=-5(-3u+5)-6u equation: 



3(u-3)-6=-5(-3u+5)-6u

We move all terms to the left:

3(u-3)-6-(-5(-3u+5)-6u)=0

We multiply parentheses

3u-(-5(-3u+5)-6u)-9-6=0



We calculate terms in parentheses: -(-5(-3u+5)-6u), so:

-5(-3u+5)-6u

We add all the numbers together, and all the variables

-6u-5(-3u+5)

We multiply parentheses

-6u+15u-25

We add all the numbers together, and all the variables

9u-25

Back to the equation:

-(9u-25)



We add all the numbers together, and all the variables

3u-(9u-25)-15=0

We get rid of parentheses

3u-9u+25-15=0

We add all the numbers together, and all the variables

-6u+10=0

We move all terms containing u to the left, all other terms to the right

-6u=-10

u=-10/-6

u=1+2/3

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