3(u-3)-7=-4(-7u+3)-7u

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Solution for 3(u-3)-7=-4(-7u+3)-7u equation:



3(u-3)-7=-4(-7u+3)-7u
We move all terms to the left:
3(u-3)-7-(-4(-7u+3)-7u)=0
We multiply parentheses
3u-(-4(-7u+3)-7u)-9-7=0
We calculate terms in parentheses: -(-4(-7u+3)-7u), so:
-4(-7u+3)-7u
We add all the numbers together, and all the variables
-7u-4(-7u+3)
We multiply parentheses
-7u+28u-12
We add all the numbers together, and all the variables
21u-12
Back to the equation:
-(21u-12)
We add all the numbers together, and all the variables
3u-(21u-12)-16=0
We get rid of parentheses
3u-21u+12-16=0
We add all the numbers together, and all the variables
-18u-4=0
We move all terms containing u to the left, all other terms to the right
-18u=4
u=4/-18
u=-2/9

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