3(u-3)-8=-3(-9u+9)-8u

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Solution for 3(u-3)-8=-3(-9u+9)-8u equation: 



3(u-3)-8=-3(-9u+9)-8u

We move all terms to the left:

3(u-3)-8-(-3(-9u+9)-8u)=0

We multiply parentheses

3u-(-3(-9u+9)-8u)-9-8=0



We calculate terms in parentheses: -(-3(-9u+9)-8u), so:

-3(-9u+9)-8u

We add all the numbers together, and all the variables

-8u-3(-9u+9)

We multiply parentheses

-8u+27u-27

We add all the numbers together, and all the variables

19u-27

Back to the equation:

-(19u-27)



We add all the numbers together, and all the variables

3u-(19u-27)-17=0

We get rid of parentheses

3u-19u+27-17=0

We add all the numbers together, and all the variables

-16u+10=0

We move all terms containing u to the left, all other terms to the right

-16u=-10

u=-10/-16

u=5/8

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