3(u-3)=2(u+3)

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Solution for 3(u-3)=2(u+3) equation: 



3(u-3)=2(u+3)

We move all terms to the left:

3(u-3)-(2(u+3))=0

We multiply parentheses

3u-(2(u+3))-9=0



We calculate terms in parentheses: -(2(u+3)), so:

2(u+3)

We multiply parentheses

2u+6

Back to the equation:

-(2u+6)



We get rid of parentheses

3u-2u-6-9=0

We add all the numbers together, and all the variables

u-15=0

We move all terms containing u to the left, all other terms to the right

u=15

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