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3(u-3)=2(u+3)
We move all terms to the left:
3(u-3)-(2(u+3))=0
We multiply parentheses
3u-(2(u+3))-9=0
We calculate terms in parentheses: -(2(u+3)), so:We get rid of parentheses
2(u+3)
We multiply parentheses
2u+6
Back to the equation:
-(2u+6)
3u-2u-6-9=0
We add all the numbers together, and all the variables
u-15=0
We move all terms containing u to the left, all other terms to the right
u=15
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