3(u-4)-5=-2(-8u+6)-3u

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Solution for 3(u-4)-5=-2(-8u+6)-3u equation: 



3(u-4)-5=-2(-8u+6)-3u

We move all terms to the left:

3(u-4)-5-(-2(-8u+6)-3u)=0

We multiply parentheses

3u-(-2(-8u+6)-3u)-12-5=0



We calculate terms in parentheses: -(-2(-8u+6)-3u), so:

-2(-8u+6)-3u

We add all the numbers together, and all the variables

-3u-2(-8u+6)

We multiply parentheses

-3u+16u-12

We add all the numbers together, and all the variables

13u-12

Back to the equation:

-(13u-12)



We add all the numbers together, and all the variables

3u-(13u-12)-17=0

We get rid of parentheses

3u-13u+12-17=0

We add all the numbers together, and all the variables

-10u-5=0

We move all terms containing u to the left, all other terms to the right

-10u=5

u=5/-10

u=-1/2

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