3(u-5)+4u=-29

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Solution for 3(u-5)+4u=-29 equation: 



3(u-5)+4u=-29

We move all terms to the left:

3(u-5)+4u-(-29)=0

We add all the numbers together, and all the variables

4u+3(u-5)+29=0

We multiply parentheses

4u+3u-15+29=0

We add all the numbers together, and all the variables

7u+14=0

We move all terms containing u to the left, all other terms to the right

7u=-14

u=-14/7

u=-2

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