3(u-5)-2=-4(-4u+8)-4u

Solution for 3(u-5)-2=-4(-4u+8)-4u equation:

3(u-5)-2=-4(-4u+8)-4u

We move all terms to the left:

3(u-5)-2-(-4(-4u+8)-4u)=0

We multiply parentheses

3u-(-4(-4u+8)-4u)-15-2=0


We calculate terms in parentheses: -(-4(-4u+8)-4u), so:

-4(-4u+8)-4u

We add all the numbers together, and all the variables

-4u-4(-4u+8)

We multiply parentheses

-4u+16u-32

We add all the numbers together, and all the variables

12u-32

Back to the equation:

-(12u-32)


We add all the numbers together, and all the variables

3u-(12u-32)-17=0

We get rid of parentheses

3u-12u+32-17=0

We add all the numbers together, and all the variables

-9u+15=0

We move all terms containing u to the left, all other terms to the right

-9u=-15

u=-15/-9

u=1+2/3