3(u-5)-5=-4(-7u+2)-9u

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Solution for 3(u-5)-5=-4(-7u+2)-9u equation:



3(u-5)-5=-4(-7u+2)-9u
We move all terms to the left:
3(u-5)-5-(-4(-7u+2)-9u)=0
We multiply parentheses
3u-(-4(-7u+2)-9u)-15-5=0
We calculate terms in parentheses: -(-4(-7u+2)-9u), so:
-4(-7u+2)-9u
We add all the numbers together, and all the variables
-9u-4(-7u+2)
We multiply parentheses
-9u+28u-8
We add all the numbers together, and all the variables
19u-8
Back to the equation:
-(19u-8)
We add all the numbers together, and all the variables
3u-(19u-8)-20=0
We get rid of parentheses
3u-19u+8-20=0
We add all the numbers together, and all the variables
-16u-12=0
We move all terms containing u to the left, all other terms to the right
-16u=12
u=12/-16
u=-3/4

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