3(u-5)=-3u-27

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Solution for 3(u-5)=-3u-27 equation:



3(u-5)=-3u-27
We move all terms to the left:
3(u-5)-(-3u-27)=0
We multiply parentheses
3u-(-3u-27)-15=0
We get rid of parentheses
3u+3u+27-15=0
We add all the numbers together, and all the variables
6u+12=0
We move all terms containing u to the left, all other terms to the right
6u=-12
u=-12/6
u=-2

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