3(v+1)+2v=5(u-1)+5

Solution for 3(v+1)+2v=5(u-1)+5 equation:

Simplifying
3(v + 1) + 2v = 5(u + -1) + 5

Reorder the terms:
3(1 + v) + 2v = 5(u + -1) + 5
(1 * 3 + v * 3) + 2v = 5(u + -1) + 5
(3 + 3v) + 2v = 5(u + -1) + 5

Combine like terms: 3v + 2v = 5v
3 + 5v = 5(u + -1) + 5

Reorder the terms:
3 + 5v = 5(-1 + u) + 5
3 + 5v = (-1 * 5 + u * 5) + 5
3 + 5v = (-5 + 5u) + 5

Reorder the terms:
3 + 5v = -5 + 5 + 5u

Combine like terms: -5 + 5 = 0
3 + 5v = 0 + 5u
3 + 5v = 5u

Solving
3 + 5v = 5u

Solving for variable 'v'.

Move all terms containing v to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + 5v = -3 + 5u

Combine like terms: 3 + -3 = 0
0 + 5v = -3 + 5u
5v = -3 + 5u

Divide each side by '5'.
v = -0.6 + u

Simplifying
v = -0.6 + u