3(v+1)+2v=5(v-1)+5

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Solution for 3(v+1)+2v=5(v-1)+5 equation: 


Simplifying
3(v + 1) + 2v = 5(v + -1) + 5

Reorder the terms:
3(1 + v) + 2v = 5(v + -1) + 5
(1 * 3 + v * 3) + 2v = 5(v + -1) + 5
(3 + 3v) + 2v = 5(v + -1) + 5

Combine like terms: 3v + 2v = 5v
3 + 5v = 5(v + -1) + 5

Reorder the terms:
3 + 5v = 5(-1 + v) + 5
3 + 5v = (-1 * 5 + v * 5) + 5
3 + 5v = (-5 + 5v) + 5

Reorder the terms:
3 + 5v = -5 + 5 + 5v

Combine like terms: -5 + 5 = 0
3 + 5v = 0 + 5v
3 + 5v = 5v

Add '-5v' to each side of the equation.
3 + 5v + -5v = 5v + -5v

Combine like terms: 5v + -5v = 0
3 + 0 = 5v + -5v
3 = 5v + -5v

Combine like terms: 5v + -5v = 0
3 = 0

Solving
3 = 0

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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