3(v+1)=8v+28

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Solution for 3(v+1)=8v+28 equation: 



3(v+1)=8v+28

We move all terms to the left:

3(v+1)-(8v+28)=0

We multiply parentheses

3v-(8v+28)+3=0

We get rid of parentheses

3v-8v-28+3=0

We add all the numbers together, and all the variables

-5v-25=0

We move all terms containing v to the left, all other terms to the right

-5v=25

v=25/-5

v=-5

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