3(v+1)=8v-32

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Solution for 3(v+1)=8v-32 equation: 



3(v+1)=8v-32

We move all terms to the left:

3(v+1)-(8v-32)=0

We multiply parentheses

3v-(8v-32)+3=0

We get rid of parentheses

3v-8v+32+3=0

We add all the numbers together, and all the variables

-5v+35=0

We move all terms containing v to the left, all other terms to the right

-5v=-35

v=-35/-5

v=+7

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