3(v+12)=11(v-1)

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Solution for 3(v+12)=11(v-1) equation: 



3(v+12)=11(v-1)

We move all terms to the left:

3(v+12)-(11(v-1))=0

We multiply parentheses

3v-(11(v-1))+36=0



We calculate terms in parentheses: -(11(v-1)), so:

11(v-1)

We multiply parentheses

11v-11

Back to the equation:

-(11v-11)



We get rid of parentheses

3v-11v+11+36=0

We add all the numbers together, and all the variables

-8v+47=0

We move all terms containing v to the left, all other terms to the right

-8v=-47

v=-47/-8

v=5+7/8

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