3(v+2)+1v=4(v-1)+9

Solution for 3(v+2)+1v=4(v-1)+9 equation:

Simplifying
3(v + 2) + 1v = 4(v + -1) + 9

Reorder the terms:
3(2 + v) + 1v = 4(v + -1) + 9
(2 * 3 + v * 3) + 1v = 4(v + -1) + 9
(6 + 3v) + 1v = 4(v + -1) + 9

Combine like terms: 3v + 1v = 4v
6 + 4v = 4(v + -1) + 9

Reorder the terms:
6 + 4v = 4(-1 + v) + 9
6 + 4v = (-1 * 4 + v * 4) + 9
6 + 4v = (-4 + 4v) + 9

Reorder the terms:
6 + 4v = -4 + 9 + 4v

Combine like terms: -4 + 9 = 5
6 + 4v = 5 + 4v

Add '-4v' to each side of the equation.
6 + 4v + -4v = 5 + 4v + -4v

Combine like terms: 4v + -4v = 0
6 + 0 = 5 + 4v + -4v
6 = 5 + 4v + -4v

Combine like terms: 4v + -4v = 0
6 = 5 + 0
6 = 5

Solving
6 = 5

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.