3(v+2)+4=5(v+1)+v

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Solution for 3(v+2)+4=5(v+1)+v equation: 



3(v+2)+4=5(v+1)+v

We move all terms to the left:

3(v+2)+4-(5(v+1)+v)=0

We multiply parentheses

3v-(5(v+1)+v)+6+4=0



We calculate terms in parentheses: -(5(v+1)+v), so:

5(v+1)+v

We add all the numbers together, and all the variables

v+5(v+1)

We multiply parentheses

v+5v+5

We add all the numbers together, and all the variables

6v+5

Back to the equation:

-(6v+5)



We add all the numbers together, and all the variables

3v-(6v+5)+10=0

We get rid of parentheses

3v-6v-5+10=0

We add all the numbers together, and all the variables

-3v+5=0

We move all terms containing v to the left, all other terms to the right

-3v=-5

v=-5/-3

v=1+2/3

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