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3(v+2)+5=2(3v-5)
We move all terms to the left:
3(v+2)+5-(2(3v-5))=0
We multiply parentheses
3v-(2(3v-5))+6+5=0
We calculate terms in parentheses: -(2(3v-5)), so:We add all the numbers together, and all the variables
2(3v-5)
We multiply parentheses
6v-10
Back to the equation:
-(6v-10)
3v-(6v-10)+11=0
We get rid of parentheses
3v-6v+10+11=0
We add all the numbers together, and all the variables
-3v+21=0
We move all terms containing v to the left, all other terms to the right
-3v=-21
v=-21/-3
v=+7
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