3(v+2)+v=2(v-1)+5

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Solution for 3(v+2)+v=2(v-1)+5 equation: 



3(v+2)+v=2(v-1)+5

We move all terms to the left:

3(v+2)+v-(2(v-1)+5)=0

We add all the numbers together, and all the variables

v+3(v+2)-(2(v-1)+5)=0

We multiply parentheses

v+3v-(2(v-1)+5)+6=0



We calculate terms in parentheses: -(2(v-1)+5), so:

2(v-1)+5

We multiply parentheses

2v-2+5

We add all the numbers together, and all the variables

2v+3

Back to the equation:

-(2v+3)



We add all the numbers together, and all the variables

4v-(2v+3)+6=0

We get rid of parentheses

4v-2v-3+6=0

We add all the numbers together, and all the variables

2v+3=0

We move all terms containing v to the left, all other terms to the right

2v=-3

v=-3/2

v=-1+1/2

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