3(v+2)+v=4(v-1)

Solution for 3(v+2)+v=4(v-1) equation:

Simplifying
3(v + 2) + v = 4(v + -1)

Reorder the terms:
3(2 + v) + v = 4(v + -1)
(2 * 3 + v * 3) + v = 4(v + -1)
(6 + 3v) + v = 4(v + -1)

Combine like terms: 3v + v = 4v
6 + 4v = 4(v + -1)

Reorder the terms:
6 + 4v = 4(-1 + v)
6 + 4v = (-1 * 4 + v * 4)
6 + 4v = (-4 + 4v)

Add '-4v' to each side of the equation.
6 + 4v + -4v = -4 + 4v + -4v

Combine like terms: 4v + -4v = 0
6 + 0 = -4 + 4v + -4v
6 = -4 + 4v + -4v

Combine like terms: 4v + -4v = 0
6 = -4 + 0
6 = -4

Solving
6 = -4

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.