3(v+2)+v=4(v-1)+10

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Solution for 3(v+2)+v=4(v-1)+10 equation:


Simplifying
3(v + 2) + v = 4(v + -1) + 10

Reorder the terms:
3(2 + v) + v = 4(v + -1) + 10
(2 * 3 + v * 3) + v = 4(v + -1) + 10
(6 + 3v) + v = 4(v + -1) + 10

Combine like terms: 3v + v = 4v
6 + 4v = 4(v + -1) + 10

Reorder the terms:
6 + 4v = 4(-1 + v) + 10
6 + 4v = (-1 * 4 + v * 4) + 10
6 + 4v = (-4 + 4v) + 10

Reorder the terms:
6 + 4v = -4 + 10 + 4v

Combine like terms: -4 + 10 = 6
6 + 4v = 6 + 4v

Add '-6' to each side of the equation.
6 + -6 + 4v = 6 + -6 + 4v

Combine like terms: 6 + -6 = 0
0 + 4v = 6 + -6 + 4v
4v = 6 + -6 + 4v

Combine like terms: 6 + -6 = 0
4v = 0 + 4v
4v = 4v

Add '-4v' to each side of the equation.
4v + -4v = 4v + -4v

Combine like terms: 4v + -4v = 0
0 = 4v + -4v

Combine like terms: 4v + -4v = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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