3(v+2)-1v=2(v-1)+5

Solution for 3(v+2)-1v=2(v-1)+5 equation:

Simplifying
3(v + 2) + -1v = 2(v + -1) + 5

Reorder the terms:
3(2 + v) + -1v = 2(v + -1) + 5
(2 * 3 + v * 3) + -1v = 2(v + -1) + 5
(6 + 3v) + -1v = 2(v + -1) + 5

Combine like terms: 3v + -1v = 2v
6 + 2v = 2(v + -1) + 5

Reorder the terms:
6 + 2v = 2(-1 + v) + 5
6 + 2v = (-1 * 2 + v * 2) + 5
6 + 2v = (-2 + 2v) + 5

Reorder the terms:
6 + 2v = -2 + 5 + 2v

Combine like terms: -2 + 5 = 3
6 + 2v = 3 + 2v

Add '-2v' to each side of the equation.
6 + 2v + -2v = 3 + 2v + -2v

Combine like terms: 2v + -2v = 0
6 + 0 = 3 + 2v + -2v
6 = 3 + 2v + -2v

Combine like terms: 2v + -2v = 0
6 = 3 + 0
6 = 3

Solving
6 = 3

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.