3(v+2)=-2(5v-8)+9v

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Solution for 3(v+2)=-2(5v-8)+9v equation: 



3(v+2)=-2(5v-8)+9v

We move all terms to the left:

3(v+2)-(-2(5v-8)+9v)=0

We multiply parentheses

3v-(-2(5v-8)+9v)+6=0



We calculate terms in parentheses: -(-2(5v-8)+9v), so:

-2(5v-8)+9v

We add all the numbers together, and all the variables

9v-2(5v-8)

We multiply parentheses

9v-10v+16

We add all the numbers together, and all the variables

-1v+16

Back to the equation:

-(-1v+16)



We get rid of parentheses

3v+1v-16+6=0

We add all the numbers together, and all the variables

4v-10=0

We move all terms containing v to the left, all other terms to the right

4v=10

v=10/4

v=2+1/2

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