3(v+2)=-2(7v-1)+5v

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Solution for 3(v+2)=-2(7v-1)+5v equation: 



3(v+2)=-2(7v-1)+5v

We move all terms to the left:

3(v+2)-(-2(7v-1)+5v)=0

We multiply parentheses

3v-(-2(7v-1)+5v)+6=0



We calculate terms in parentheses: -(-2(7v-1)+5v), so:

-2(7v-1)+5v

We add all the numbers together, and all the variables

5v-2(7v-1)

We multiply parentheses

5v-14v+2

We add all the numbers together, and all the variables

-9v+2

Back to the equation:

-(-9v+2)



We get rid of parentheses

3v+9v-2+6=0

We add all the numbers together, and all the variables

12v+4=0

We move all terms containing v to the left, all other terms to the right

12v=-4

v=-4/12

v=-1/3

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