3(v+2)=-2(9v-2)+9v

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Solution for 3(v+2)=-2(9v-2)+9v equation: 



3(v+2)=-2(9v-2)+9v

We move all terms to the left:

3(v+2)-(-2(9v-2)+9v)=0

We multiply parentheses

3v-(-2(9v-2)+9v)+6=0



We calculate terms in parentheses: -(-2(9v-2)+9v), so:

-2(9v-2)+9v

We add all the numbers together, and all the variables

9v-2(9v-2)

We multiply parentheses

9v-18v+4

We add all the numbers together, and all the variables

-9v+4

Back to the equation:

-(-9v+4)



We get rid of parentheses

3v+9v-4+6=0

We add all the numbers together, and all the variables

12v+2=0

We move all terms containing v to the left, all other terms to the right

12v=-2

v=-2/12

v=-1/6

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