3(v+2)=-7-5(v+7)

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Solution for 3(v+2)=-7-5(v+7) equation: 



3(v+2)=-7-5(v+7)

We move all terms to the left:

3(v+2)-(-7-5(v+7))=0

We multiply parentheses

3v-(-7-5(v+7))+6=0



We calculate terms in parentheses: -(-7-5(v+7)), so:

-7-5(v+7)

determiningTheFunctionDomain
-5(v+7)-7

We multiply parentheses

-5v-35-7

We add all the numbers together, and all the variables

-5v-42

Back to the equation:

-(-5v-42)



We get rid of parentheses

3v+5v+42+6=0

We add all the numbers together, and all the variables

8v+48=0

We move all terms containing v to the left, all other terms to the right

8v=-48

v=-48/8

v=-6

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