3(v+2)=4(v-1)+10

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Solution for 3(v+2)=4(v-1)+10 equation: 



3(v+2)=4(v-1)+10

We move all terms to the left:

3(v+2)-(4(v-1)+10)=0

We multiply parentheses

3v-(4(v-1)+10)+6=0



We calculate terms in parentheses: -(4(v-1)+10), so:

4(v-1)+10

We multiply parentheses

4v-4+10

We add all the numbers together, and all the variables

4v+6

Back to the equation:

-(4v+6)



We get rid of parentheses

3v-4v-6+6=0

We add all the numbers together, and all the variables

-v=0

v=0/-1

v=0

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