3(v+3)+v=2(v-1)-3

Solution for 3(v+3)+v=2(v-1)-3 equation:

3(v+3)+v=2(v-1)-3

We move all terms to the left:

3(v+3)+v-(2(v-1)-3)=0

We add all the numbers together, and all the variables

v+3(v+3)-(2(v-1)-3)=0

We multiply parentheses

v+3v-(2(v-1)-3)+9=0


We calculate terms in parentheses: -(2(v-1)-3), so:

2(v-1)-3

We multiply parentheses

2v-2-3

We add all the numbers together, and all the variables

2v-5

Back to the equation:

-(2v-5)


We add all the numbers together, and all the variables

4v-(2v-5)+9=0

We get rid of parentheses

4v-2v+5+9=0

We add all the numbers together, and all the variables

2v+14=0

We move all terms containing v to the left, all other terms to the right

2v=-14

v=-14/2

v=-7