3(v+3)+v=2(v-1)-3

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Solution for 3(v+3)+v=2(v-1)-3 equation:



3(v+3)+v=2(v-1)-3
We move all terms to the left:
3(v+3)+v-(2(v-1)-3)=0
We add all the numbers together, and all the variables
v+3(v+3)-(2(v-1)-3)=0
We multiply parentheses
v+3v-(2(v-1)-3)+9=0
We calculate terms in parentheses: -(2(v-1)-3), so:
2(v-1)-3
We multiply parentheses
2v-2-3
We add all the numbers together, and all the variables
2v-5
Back to the equation:
-(2v-5)
We add all the numbers together, and all the variables
4v-(2v-5)+9=0
We get rid of parentheses
4v-2v+5+9=0
We add all the numbers together, and all the variables
2v+14=0
We move all terms containing v to the left, all other terms to the right
2v=-14
v=-14/2
v=-7

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